Hi.
I am interested in explanation on how to calculate the heating load of a single room, if we know the annual heating degree hours? But doing this by hand, not using EnergyPlus, DOE or similar energy analysis application. I just want to understand the principle for now.
Is this is the right approach:
heating load (per hour) = total heat loss (per hour) * thermal transmittance coefficient of room's windows/walls/doors/floor/ceiling?
For the sake of simplicity let's say that our single room is made of bricks (both four walls, ceiling and floor), that it has no windows, nor doors. The room is a brick of dimensions 3x3x3 meters. It has no rooms around it, basically it's one room house. The thermal transmitance coefficient (U) for brick wall = 0.0026 kW/m2*C Let's also assume that there is no heat loss through ventilation nor heat gains.
heatLoss through each room wall/ceiling/floor is = 3*3 * 0.0026 = 0.0234 kW/C. For all six "sides" of the room, it is = 6 * 0.0234 = 0.1404 kW/C
Let's assume that for some particular hour during a year, the heating degree hour is 20 C (in winter for example).
Does that mean that for that particular hour, the heating load of our room is: 0.1404 * 20 = 2.808 kW?
Did I understand this correctly?
Thank you for the reply.
