# How to calculate heating load based on heating degree hours?

Hi.

I am interested in explanation on how to calculate the heating load of a single room, if we know the annual heating degree hours? But doing this by hand, not using EnergyPlus, DOE or similar energy analysis application. I just want to understand the principle for now.

Is this is the right approach:

heating load (per hour) = total heat loss (per hour) * heating degree hour

For the sake of simplicity let's say that our single room is made of bricks (both four walls, ceiling and floor), that it has no windows, nor doors. The room is a brick of dimensions 3x3x3 meters. It has no rooms around it, basically it's one room house. The thermal transmitance coefficient (U) for brick wall = 0.0026 kW/m2*C Let's also assume that there is no heat loss through ventilation nor heat gains.

heatLoss through each room wall/ceiling/floor is = 3*3 * 0.0026 = 0.0234 kW/C. For all six "sides" of the room, it is = 6 * 0.0234 = 0.1404 kW/C

Let's assume that for some particular hour during a year, the heating degree hour is 20 C (in winter for example).

Does that mean that for that particular hour, the heating load of our room is: 0.1404 * 20 = 2.808 kW?

Did I understand this correctly?

Thank you for the reply.

@georges, did you see this question yet? How to describe climate data / calculate degree days? Please search before you post. If the answer is not there, it helps others if you can reference the older post and explain why you need a new question.

Thank you for your reply Neal. You seemed to misunderstand my question. I am not looking for a way to calculate the heating/cooling degree days. I already have heating (or cooling does not matter) degree hours, and based on this I would like to calculate a heat loss of a certain room, for a particular hour.

@georges My apologies. I didn't read the question thoroughly.