Question-and-Answer Resource for the Building Energy Modeling Community
Get s tarted with the Help page

# Insulation layer in idf file

Following is the Exterior Wall information in the IDF file, which layer is the insulation layer?

  Construction,
Exterior Wall,           !- Name
Stucco_1in,              !- Outside Layer
Bldg_paper_felt,         !- Layer 2
sheathing_consol_layer,  !- Layer 3
OSB_5/8in,               !- Layer 4
wall_consol_layer,       !- Layer 5
Drywall_1/2in;           !- Layer 6

Material:NoMass,
Bldg_paper_felt,         !- Name
Smooth,                  !- Roughness
1.05666113069662E-02;    !- Thermal Resistance {m2-K/W}

Material,
sheathing_consol_layer,  !- Name
Rough,                   !- Roughness
0.0127,                  !- Thickness {m}
0.0940184,               !- Conductivity {W/m-K}
685.008,                 !- Density {kg/m3}
1172.332;                !- Specific Heat {J/kg-K}

Material,
OSB_5/8in,               !- Name
MediumSmooth,            !- Roughness
0.015875032180756,       !- Thickness {m}
0.1163,                  !- Conductivity {W/m-K}
544.627399310259,        !- Density {kg/m3}
1213.36000918149;        !- Specific Heat {J/kg-K}

Material,
wall_consol_layer,       !- Name
Rough,                   !- Roughness
0.1397,                  !- Thickness {m}
0.05966275,              !- Conductivity {W/m-K}
120.801,                 !- Density {kg/m3}
1036.25775;              !- Specific Heat {J/kg-K}

edit retag close merge delete

Sort by ยป oldest newest most voted

You just have to calculate the R-value of materials:

$$R = \frac{e}{\lambda}$$

Where:

• $R$: Thermal Resistance ($m^2 \cdot K \cdot W^{-1}$)
• $e$: Thickness ($m$)
• $\lambda$: Conductivity ($W \cdot m^{-1} \cdot K^{-1}$)

So your insulation layer is wall_consol_layer:

It also has a low density, which is typical of insulation (since mostly it's the air trapped in the material that provides the insulaton...).

more

## Stats

Seen: 75 times

Last updated: Dec 03 '19